Can someone please help me on this one!

Answer:
The answer is (1,-1)
Step-by-step explanation:
The best approach for this problem is to plug in the coordinates into the given inequality.
[tex]7x-3y\geq 10\\[/tex]
(3,4) ------> [tex]7(3)-3(4)=9[/tex]
9 is less than 10 so, we can rule this one out.
(1,0) -------> [tex]7(1)-3(0)=7[/tex]
7 is less than 10 so, we can rule this one out.
(1,2) -------> [tex]7(1)-3(2)=1[/tex]
1 is less than 10 so, we can rule this one out.
(1,-1) -------> [tex]7(1)-3(-1)=10[/tex]
10 is equal to 10, so this is the answer.
Hope this helps!
As mentioned by Mark there are an unlimited number of pairs that satisfy your equation. So let us see how you can characterize these solutions
if 7x - 3y > 10 then
7x > 10 +3y
Now we can substitute any value for y and get the appropriate value for x. For example I can choose y to be 6
then by substitution
7 must be > 10+ 3*6
or 7x must be > 28
or x must be > 4
So all pairs such that x is > 4 and y = 6 are solutions.
I can create an infinite number of pairs choosing any number for y. Likewise I could have chosen x and solved the problem for y. In the above example I chose 6 for y to make the division easy. I could have chosen any number(real or integer) for y and solved the equation for x to derive appropriate pairs