Respuesta :

Answer:

7 and 8

Step-by-step explanation:

Consider the perfect squares either side of 51

49 < 51 < 64 , thus

[tex]\sqrt{49}[/tex] < [tex]\sqrt{51}[/tex] < [tex]\sqrt{64}[/tex] , that is

7 < [tex]\sqrt{51}[/tex] < 8

oscar236

Answer:

7 and 8.

Step-by-step explanation:

7^2 = 49 and 8^2 = 64.