Step-by-step explanation:
Given that,
The area of a blackboard is [tex]1\dfrac{1}{3}=\dfrac{4}{3}\ \text{yards}^2[/tex]
The area of poster is [tex]\dfrac{8}{9}\ \text{yards}^2[/tex]
We need to find the unit rate of the blackboard's area to the poster's area. So, it can be calcualted by dividing blackboard's area to the poster's area.
So,
[tex]\dfrac{\dfrac{4}{3}}{\dfrac{8}{9}}=\dfrac{4}{3}\times \dfrac{9}{8}\\\\=1.5[/tex]
So, the rate of [tex]1.5\ \text{yard}^2[/tex].
