Answer:
1.0625×10¹⁹ electrons
Explanation:
From the question,
Using,
Q = It........................ Equation 1
Where Q = charge, I = current flowing in the wire, t = time (seconds)
Given: I = 1.70 A, t = 1 Seconds.
Substitute these values into equation 1
Q = 1.7(1)
Q = 1.7 C.
But,
1.6×10⁻¹⁹ C = 1 electron
Therefore,
1.7 C = 1.7/(1.6×10⁻¹⁹) electrons
= 1.0625×10¹⁹ electrons
Hence, 1.0625×10¹⁹ electrons flows through the wire per seconds.
