Respuesta :

Answer : The area of the figure composed of a parallelogram, a square and a rectangle is 126 in².

Step-by-step explanation :

Area of composed figure = Area of parallelogram + Area of square + Area of rectangle

First we have to calculate the area of parallelogram.

Area of parallelogram = Base × Height

Given:

Base = 10 in

Height = 3.5 in

Area of parallelogram = 10 in × 3.5 in

Area of parallelogram = 35 in²

Now we have to calculate the area of square.

Area of square = (Side)²

Given:

Side = 4 in

Area of square = (4 in)²

Area of square = 16 in²

Now we have to calculate the area of rectangle.

Area of rectangle = Length × Breadth

Given:

Length = 12.5 in

Breadth = 6 in

Area of rectangle = 12.5 in × 6 in

Area of rectangle = 75 in²

Now we have to calculate the composed figure.

Area of composed figure = Area of parallelogram + Area of square + Area of rectangle

Area of composed figure = 35 in² + 16 in² + 75 in²

Area of composed figure = 126 in²

Therefore, the area of the figure composed of a parallelogram, a square and a rectangle is 126 in².

abidemiokin

The area of the given figure is 126in²

Composite figures

The given figure is a composite figure composed of a parallelogram, a square and a rectangle.

Get the area of the square

Area = L²

Area of the square = 4² = 16in²

Area of the rectangle = 6 * 12.5

Area of the rectangle = 75in²

For the parallelogram:

Area of the parallelogram = Base * Height

Area of the parallelogram = 10 * 3.5

Area of the parallelogram  = 35 in²

Area of the figure = 75in² + 35in² + 16in²

Area of the figure = 126in²

Hence the area of the figure is 126in²

Learn more on area of composite figures here: https://brainly.com/question/10254615

Otras preguntas