Answer:
$6.36
Step-by-step explanation:
this is a system of equations problem. There are two main methods for this type of problem: elimination and substitution(I used both here). A-croissants, B-coffee.
The cost of an order of 1 croissant is $2.3 and 1 cup of coffee is $4.05.
We need to form the system of equations for the given statement.
In mathematics, a set of simultaneous equations, also known as a system of equations or an equation system, is a finite set of equations for which common solutions are sought.
Let the cost of croissants be x and the cost of cups of coffee be y.
6 croissants and 3 cups of coffee costs $25.95
6x+3y=25.95-----(1)
1 croissant and 6 cups of coffee cost $26.70
x+6y=26.70-----(2)
(6x+3y)6=25.95×6
⇒36x+18y=155.7-----(3)
(x+6y)3=26.70×3
⇒3x+18y=80.1-----(4)
Subtract (4) from (3).
That is, 36x+18y-(3x+18y)=155.7-80.1
⇒33x=75.6
⇒x=2.3
Substitute x=2.3 in equation (1).
That is, 6(2.3)+3y=25.95
⇒3y=12.15
⇒y=4.05
Therefore, the cost of an order of 1 croissant is $2.3 and 1 cup of coffee is $4.05.
To learn more about the system of equations visit:
https://brainly.com/question/21620502.
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