perimeter help please quick !

Answer:
[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{x = 4.4}}}}}[/tex]
Step-by-step explanation:
Given,
Length of the rectangle ( l ) = 3x + 5
Breadth of the rectangle ( b ) = 2x - 1
Perimeter of the rectangle ( P ) = 52
Finding the value of x
[tex] \boxed{ \sf{perimeter \: of \: rectangle = 2(l + b)}}[/tex]
⇒[tex] \sf{52 = 2(3x + 5 + 2x - 1)}[/tex]
⇒[tex] \sf{52 = 2(5x + 4)}[/tex]
⇒[tex] \sf{52 = 10x + 8}[/tex]
⇒[tex] \sf{10x + 8 = 52}[/tex]
⇒[tex] \sf{10x = 52 - 8}[/tex]
⇒[tex] \sf{10x = 44}[/tex]
⇒[tex] \sf{ \frac{10x}{10} = \frac{44}{10} }[/tex]
⇒[tex] \sf{x = 4.4 \: }[/tex]
Hope I helped!
Best regards!! :D