Answer:
Step-by-step explanation:
[tex](-3,-3) =(x_1,y_1)\\ (-6,1)=(x_2,y_2)\\\\d = \sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}\\ \\d = \sqrt{(-6-(-3))^2+(1-(-3))^2}\\ \\d = \sqrt{(-6+3)^2+(1+3)^2}\\ \\d = \sqrt{(-3)^2 +(4)^2}\\ \\d = \sqrt{9+16}\\ \\d = \sqrt{25}\\ \\d =5[/tex]
