Charlie and Clare are playing a number-guessing game. Charlie picked two numbers between 1 and 5. To win the game, Clare must guess both his numbers in three tries. Her guesses, simulated using a random-number generator, are shown in the table. If Charlie’s numbers are 1 and 3, what is the experimental probability that Clare won?

The probability is defined as the possibility of an event is equal to the ratio of the number of favorable outcomes and the total number of outcomes.

Charlie picked two numbers between 1 and 5

So the numbers should be 2, 3, and 4

There is the number of favorable outcomes is 3

To win the game, Clare must guess both his numbers in three tries

The experimental probability that Clare won if Charlie's numbers were 1 and 3 = P(E)

There are 10 trials given

There are total number of possible outcomes is 10

So the required experimental probability P(E) = favorable outcomes/total outcomes

⇒ P(E) = 3/10

Hence, the experimental probability is 3/10 that Clare won if Charlie's numbers were 1 and 3.

Learn more about the probability here:

brainly.com/question/11234923

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