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The maximum velocity of a particle executing simple harmonic motion with amplitude 7.0 mm is 4.4 m/s. The period of oscillation is? A. 0.5 s B. 0.1 s C. 100 s D. 0.01 s E. 10 s Reset Selection

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MathPhys

Answer:

D. 0.01 s

Explanation:

The maximum speed is the amplitude times the angular frequency.

v = Aω

4.4 m/s = (0.0070 m) ω

ω = 628.6 rad/s

The period is:

ω = 2π / T

T = 2π / ω

T = 2π / (628.6 rad/s)

T = 0.01 s

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