Answer:
8.13 g/mol.
Explanation:
The following formula gives us the relationship between the effusion rates of two gases and their molar masses:
[tex]\sqrt{\frac{MM_{x} }{MM_{y} } } = \frac{rate_{y} }{rate_{x} }[/tex]
where x and y are respective sample gases and MM and rate are molar mass and rate of effusion respectively.
⇒[tex]\sqrt{\frac{14}{y} } = \frac{63}{48}[/tex]
[tex]\frac{14}{y} = 1.3125^{2}[/tex]
y= 14 / [tex]1.3125^{2}[/tex] = 8.13 g/mol.
