Answer:
[tex]N_2~+~3H_2~+~4O_2~->~2HNO_3~+~2H_2O[/tex]
Explanation:
We can start with the reaction of hydrogen and nitrogen to produce ammonia, so:
[tex]N_2~+~H_2~->~NH_3[/tex]
When we balance the reaction we will obtain:
[tex]N_2~+~3H_2~->~2NH_3[/tex]
Now, the production of nitric acid with oxygen would be:
[tex]NH_3~+~O_2~->~HNO_3~+~H_2O[/tex]
If we balance the reaction we will obtain:
[tex]NH_3~+~2O_2~->~HNO_3~+~H_2O[/tex]
Now, if we put the reactions together we will obtain:
[tex]N_2~+~3H_2~->~2NH_3[/tex]
[tex]NH_3~+~2O_2~->~HNO_3~+~H_2O[/tex]
We can multiply the second reaction by "2":
[tex]N_2~+~3H_2~->~2NH_3[/tex]
[tex]2NH_3~+~4O_2~->~2HNO_3~+~2H_2O[/tex]
We have "[tex]2NH_3[/tex]" on both sides. In the first reaction is in the right in the second reaction is on the left. Therefore we can cancel out this compound and we will obtain:
[tex]N_2~+~3H_2~+~4O_2~->~2HNO_3~+~2H_2O[/tex]
On this reaction, we will have 2 nitrogen atoms on both sides, 6 hydrogen atoms on both sides, and 8 oxygen atoms on both sides. So, this would be the net reaction for the production of nitric acid.