Answer:
Question 3: 582 ft²
Question 4: 348 in²
Step-by-step Explanation:
Question 3:
Consider the solid shape given as being consisting of two rectangular prism. With careful examination, you'd observe that the offer one beneath has dimensions, [tex] l, w, h, as 15, 4, 9 [/tex]
The second one has [tex] l, w, h, as 6, 4, 6 [/tex]
Surface area of the bigger rectangular prism = total surface area - area of the surface that is joined to the smaller rectangular prism.
Area of the face joined to the smaller rectangular prism = 4*6 = 24 ft²
Surface area of the bigger rectangular prism = [tex] 2(wl + hl + hw) - 24 [/tex]
[tex] 2(4*15 + 9*15 + 9*4) - 24 [/tex]
[tex] 462 - 24 [/tex]
Surface area of the bigger rectangular prism = 438 ft²
Surface area of the smaller rectangular prism = total surface area of rectangular prism - area of the surface that is joined to the bigger rectangular prism.
= [tex] 2(wl + hl + hw) - 24 [/tex]
[tex] = 2(4*6 + 6*6 + 6*4) - 24 [/tex]
[tex] = 168 - 24 = 144 ft^2 [/tex]
Surface area of the solid = 438 + 144 = 582 ft²
Question 4:
Surface area of the triangular prism is given as: 2(B.A) + P*L
Where,
B.A = area of 1 triangular base = ½*height of the triangle*base of the traingle
B.A = ½*6*16 = 3*16 = 48 in²
P = perimeter of 1 triangular base = sum of all sides of the triangle.
P = 16+10+10 = 36 in
L = length or height of prism =
Plug in the values to find surface area of the prism
Surface area = 2(B.A) + P*L
= 2(48) + 36*7 = 96 + 252 = 348 in²
Surface area of prism = 348 in²
