Answer:
The fourth
Step-by-step explanation:
[tex]x^2+y^2-14x+10y+25=0\\\\x^2-14x\ +\ y^2+10y+25=0\\\\\underline{x^2-14x+49} -49+\underline{y^2+10y+25}=0\\\\\underline{x^2-2\cdot x\cdot7+7^2}-49+\underline{y^2+2\cdot y\cdot5+5^2}=0 \\\\\underline{(x-7)^2}-49+\underline{(y+5)^2}=0\\\\\underline{\underline{(x-7)^2+(y+5)^2=49}}[/tex]
