Answer:
W = 1 J
Explanation:
Given that,
A constant force, [tex]F=2i+3j-5k[/tex]
The particle displaces it from (1,2,-3) m to (2,5,-1) m. We need to find the work done by the force.
The position vector from (1,2,-3) m to (2,5,-1) m is (2-1, 5-2, -1-(-3)) i.e. (1, 3, 2) m
Work done is given by :
[tex]W=F{\cdot} d\\\\W=(2i+3j-5k){\cdot} (i+3j+2k)[/tex]
From dot product, i.i = j.j = k.k = 1
So,
[tex]W=2+3\times 3-5\times 2\\\\W=1\ J[/tex]
So, the work done by the force is 1 J.
