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3/x-2, i'm confused as to what the horizontal asymptote is. The resources I found online conclude that it has a horizontal asymptote of y=0. I know that in order for a horizontal asymptote to be y=0, the denominator has to have a greater degree than the numerator. Im confused because doesn't the numerator have the same degree as the denominator (degree of 1)?

Respuesta :

Answer:

y = 0

Step-by-step explanation:

Given

f(x) = [tex]\frac{3}{x-2}[/tex]

The degree of the numerator is zero 0 (  3[tex]x^{0}[/tex] )

The degree of the denominator is 1

Since the degree of denominator > degree of numerator.

Then there is a horizontal asymptote at y = 0

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