Answer:
[tex]\boxed{\frac{-3b^4 }{a^6 }}[/tex]
Step-by-step explanation:
[tex]\frac{-18a^{-8}b^{-3}}{6a^{-2}b^{-7}}[/tex]
[tex]\frac{-18}{6} \times \frac{a^{-8}}{a^{-2}} \times \frac{b^{-3}}{b^{-7}}[/tex]
[tex]-3 \times \frac{a^{-8}}{a^{-2}} \times \frac{b^{-3}}{b^{-7}}[/tex]
Apply the law of exponents, when dividing exponents with same base, we subtract the exponents.
[tex]-3 \times a^{-8-(-2)} \times b^{-3- (-7)}[/tex]
[tex]-3 \times a^{-8+2} \times b^{-3+7}[/tex]
[tex]-3 \times a^{-6} \times b^{4}[/tex]
[tex]{-3a^{-6}b^{4}}[/tex]
The answer should be without negative exponents.
[tex]a^{-6}=\frac{1}{a^6 }[/tex]
[tex]\frac{-3b^4 }{a^6 }[/tex]
