Answer:
[tex]\frac{1}{3} y[/tex] - [tex]\frac{7}{5}x[/tex] + [tex]\frac{2}{3}[/tex] - [tex]\frac{2}{3} y[/tex] - [tex]\frac{4}{9}[/tex]
Step-by-step explanation:
We are to find the expression which is equivalent to;
[tex]-\frac{2}{3}y[/tex] - [tex]\frac{3}{5} x[/tex] + [tex]\frac{2}{9}[/tex] - [tex]\frac{4}{5}x[/tex] + [tex]\frac{1}{3}y[/tex]
Putting the like terms together we get;
[tex]-\frac{2}{3}y[/tex] + [tex]-\frac{2}{3}y[/tex] - [tex]\frac{3}{5} x[/tex] - [tex]\frac{4}{5}x[/tex] + [tex]\frac{2}{9}[/tex]
Simplifying this gives;
[tex]-\frac{1}{3}y[/tex] - [tex]\frac{7}{5}x[/tex] + [tex]\frac{2}{9}[/tex]
The equation that is equivalent to this answer from the choices is;
[tex]\frac{1}{3} y[/tex] - [tex]\frac{7}{5}x[/tex] + [tex]\frac{2}{3}[/tex] - [tex]\frac{2}{3}y[/tex] - [tex]\frac{4}{9}[/tex]
