Answer: [tex]x=0\text{ and }x=e^4[/tex]
Step-by-step explanation:
Given function: [tex]f(x) = \ln(4 - \ln(x))[/tex]
Since, [tex]\ln 0=\infty[/tex]
Here, if
[tex]f(x)\to \infty\\\Rightarrow\ 4-\ln x=0\Rightarrow\ln x=4\Rightarrow\ x=e^4\\\text{OR}\ln x=\infty\Rightarrow\ x=0[/tex]
Hence, the vertical asymptotes of f(x) are:
[tex]x=0\text{ and }x=e^4[/tex].
Using it's concept, it is found that the vertical asymptotes of the function are: [tex]\mathbf{x = 0, x = e^4}[/tex]
A vertical asymptote of a function f(x) are the values of x for which the function is outside it's domain.
For the ln function, that is, [tex]\ln{g(x)}[/tex], they are the values of x for which:
[tex]g(x) = 0[/tex]
In this problem, the function is:
[tex]f(x) = \ln{(4 - \ln{(x)})}[/tex]
For the inner function, x = 0 is a vertical asymptote, as [tex]\ln{0}[/tex] is outside the domain.
For the outer function:
[tex]4 - \ln{(x)} = 0[/tex]
[tex]\ln{(x)} = 4[/tex]
[tex]e^{\ln{(x)}} = e^4[/tex]
[tex]x = e^4[/tex]
A similar problem is given at https://brainly.com/question/23535769
