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A lot consisting of 50 bulbs is inspected by taking at random 10 bulbs and testing them. If the number of defective bulbs is at most 1, the lot is accepted; otherwise it is rejected. If there are 10 defective bulbs in the lot, what is the probability of accepting the lot?

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emoffett3223

Answer:

0.3487

Step-by-step explanation:

The probability of accepting the lot If there are 10 defective bulbs in the lot is;  0.3487

  • This involves binomial probability distribution which is given by the formula;

P(X = r) = ⁿ[tex]C_{r}[/tex] × [tex]p^{r}[/tex] × [tex]q^{1 - r}[/tex]

  • We are given;

Number of bulbs taken at random = 10

We are told that if the number of defective bulbs is at most 1, then the lot is accepted.

This means that probability of success is; p = 1/10 = 0.1

q = 1 - p

q = 1 - 0.1

q = 0.9

  • If there are 10 defective bulbs, then the probability of accepting the lot is;

P(X = 0) = ¹⁰[tex]C_{0}[/tex] × [tex]0.1^{0}[/tex] × [tex]0.9^{10 - 0}[/tex]

P(X = 0) = 0.3487

Read more at; https://brainly.com/question/24239758

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