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Rectangle ABCD is graphed in the coordinate plane. The following are the vertices of the rectangle: A(-8, -6), B(-3,-6), C(-3, -4), and D(-8, -4). Given these coordinates, what is the length of side AB of this rectangle?

Respuesta :

devishri1977

Answer:

Step-by-step explanation:

Distance = [tex]\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}[/tex]

A(-8,-6)   ; B(-3,-6)

[tex]AB= \sqrt{(-3-[-8])^{2}+(-6-[-6])^{2}}\\\\=\sqrt{(-3+8)^{2}+(-6+6)^{2}}\\\\=\sqrt{(5)^{2}+ 0}\\\\= 5 units[/tex]

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