Answer:
A) 3 interactions
B) 2.78 m/s
C) 2.78 m/s
D) 0 m/s
Explanation:
Given Data :
plastic buttons ( 2 ) = 2.0 g each
charge on each plastic buttons = +65 nC
A) The interactions that have potential energy can be expressed as
V net = v1 + v2 + v3
V net = 0 + [tex]\frac{kq1q2}{r12} + \frac{kq1q3}{r13} + \frac{kq2q3}{r23}[/tex]
hence the total interactions is (3)
B) The final speed of the left 2.0 g plastic button
U = [tex]\frac{9*10^9* 10^-18}{0.02} [ 65*250 + 65*250 + (65*65)/2 ][/tex]
U = 0.0155 J
also U = [tex]2( 1/2 mv^2 )[/tex]
U = mv^2 = 0.0155 J
therefore ; v = [tex]\sqrt{0.0155/(2*10^-3)}[/tex] = 2.78 m/s
C) final speed of the right 2.0 g plastic button = Final speed of the right 2.0 g plastic button
v = 2.78 m/s
D) The final speed of the 5.0 g plastic button
= 0 m/s
