Answer:
0.5216
Step-by-step explanation:
Given the function y =kx(1-x), the pattern of attractors are the value(s) of y at the initial value of k and x. Given the value of k = 3.26 and x = 0.8, to get the pattern of attractors, we will substitute the given initial value into the function as shown;
[tex]y =kx(1-x)\\\\y = 3.26(0.8)(1-0.8)\\\\y = 3.26*0.8*0.2\\\\y = 0.5216\\\\[/tex]
Hence, the pattern of attractor for the equation y is 0.5216
