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Bumper car A (331 kg) moving east at 3.87 m/s hit stationary car B (208 kg). After, the car A moves .88 m/s east. What is the velocity of car B?

Respuesta :

nobleswift

Answer:

Ub = 221.99m/s

Explanation:

(Ma x Ua)+(Mb x Ub) = (Ma + Mb)V

(331 x 3.87)+(208 x Ub) = (331 + 208)88

(1257.8) + (208 x Ub) = 47432

(208 x Ub) = 47432 - 1257.8

(208 x Ub) = 46174.2

Ub = 46174.2/208 = 221.99m/s

Ub = 221.99m/s

Answer:

4.75

Explanation:

M1V1 + M2V2 = M1V3 + M2V4

[(331*3.87) , 90°] + 0 = [(331*0.888) , 90°] + M2V4

M2V4 = 987.042 , 90°

divide through by M2

V4 = 4.75 m/s east