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Bumper car A (281 kg) moving +2.82 m/s makes an elastic collision with bumper car B (209 kg) moving +1.72 m/s. What is the velocity of car B after the collision?

Respuesta :

nobleswift

Answer:

V = 2.35m/s

Explanation:

(Ma x Ua) + (Mb x Ub) = (Ma x Mb)V

(281 x 2.82) + (209 x 1.72) = (281 + 209)V

(792.42) + (359.48) = (490)V

1151.9 = 490V

V = 1151.9/490 = 2.35m/s

V = 2.35m/s

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