Answer:
length of C'B' = 15units (B)
Step-by-step explanation:
Original image is ∆ABC
A = (8,15)
B = (12, 13)
C = (8,10)
Scale factor = 3
Since the circle would be dilated by a scale factor of 3 about the origin, Do(x,y) →3(x,y)
Coordinates of ∆A'B'C'
A' = 3(8, 15) = (24, 45)
B' = 3(12, 13) = (36, 39)
C' = 3(8, 10) = (24, 30)
The distance formula = √(x2 - x1)² + (y2-y1)²
Where x2 = x subscript 2, x1 = x subscript 1; y2 = y subscript 2, y1 = y subscript 1
Length C'B' = Distance between B' and C'
See attachment for details
From the solution, length of C'B' = 15units (B)
