Respuesta :
Answer:
Approximately normal for large sample sizes
Step-by-step explanation:
The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].
For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.
In this question:
The distribution is unknown, so the sampling distribution will only be approximately normal when n is at least 30.
So the correct answer should be:
Approximately normal for large sample sizes
For a population where the distribution is unknown, the sampling distribution of the sample mean will be: b. approximately normal for all sample sizes
Recall:
- Based on the Central Limit Theorem, the sampling distribution of the sample mean for either skewed variable or normally distributed variable can be approximated to a normal distribution given the mean and standard deviation.
- The central Limit Theorem holds true provided, n greater than or equal to 30.
Therefore, for a population where the distribution is unknown, the sampling distribution of the sample mean will be: b. approximately normal for all sample sizes
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