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4.AsampleoffruithasapHof4.2.Whatistheconcentrationinmoldm-3ofhydroxideions, [OH -]inthejuice?A.1.58x10 -5 B.1.58x10 -10 C.6.31x10 -5 D.9.80x10

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Answer:  B. 1.58 x 10 ∧ -10 mol/dm3 of OH- ions

Explanation:

pOH = - log [OH-]

It is well known that; pH + pOH = 14

That is to say; 4.2 + pOH = 14, therefore; pOH = 14 - 4.2 = 9.8

9.8  = - log [OH-]

In other to get the concentration, we take the anti-log of 9.8 .

Anti-log of 9.8 = 1.58 x 10 ∧ -10mol/dm3.

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