mirembefg
contestada

2x − 5y = 16 3x + 2y = 5 Hi! Can you please help me with this? I've tried it but I just can't seem to figure it out! If you can,please provide an explanation.Thanks,have a good day!

Respuesta :

Answer:

y=2 and x=3

Step-by-step explanation:

2x-5y=16                  equation 1

3x+2y=5                    equation 2

multiplying equation 1 by 3 and equation 2 by 2 so that 6x-6x cancel each other

3(2x-5y=16)     6x-15y=48  equation 3

2(3x+2y=5)      6x+4y=10    equation 4

substracting equation 3 and equation 4

6x-15y=48

-6x-4y=-10 changing sign

-19y=38

y=-38/19

y=-2

putting the value of y in equation 1

2x-5(-2)=16

2x+10=16

2x=16-10

2x=6

x=6/2

x=3

  i have checked the values these are correct

i hope this will help you :)    

tramserran

Answer: x = 3, y = -2   →    (3, -2)

Step-by-step explanation:

Using Elimination Method, multiply the equations by a number that allows the coefficients of either x or y to be the same number with opposite signs. Then add the two equations to solve solve for the remaining variable.

I choose to eliminate x:

2x - 5y = 16    -->   3(2x - 5y = 16)   -->    6x - 5y  = 48

3x + 2y = 5    -->   -2(3x + 2y = 5)   -->   -6x - 4y = -10

                                                                     -19y = 38

                                                                    ÷19    ÷19

                                                                        y  =  -2

Next, substitute y = -2 into either equation to solve for x.

I choose the 1st equation:

2x -  5y  = 16

2x - 5(-2) = 16

2x +  10   = 16

2x            = 6

x             = 3

Check your answer by inputting x = 3 and y = -2 into the other (2nd) equation:

3x + 2y = 5

3(3) + 2(-2) = 5

9    +   -4    = 5

      5          = 5  [tex]\checkmark[/tex]

Otras preguntas