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The straight line L has the equation 4y=5x+3
The point A has coordinates (3,-2)
Find the equation of the straight line that is perpendicular to L and passes through A
Write your answer in the form y=Mx+c

Respuesta :

ZJSG09112007

Answer:

y = -4/5x + 2/5

Step-by-step explanation:

[tex]4y=5x+3\\write -in ; y=mx+b -form\\y = \frac{5}{4} x + \frac{3}{4} \\m = 5/4\\m_1m_2 = -1\\5/4m_2 =-1\\m_2 = -4/5\\ (3,-2)\\x = 3\\y = -2\\y = mx+b\\-2 = -\frac{4}{5}(3) +b\\-2 = -12/5 +b\\-2+12/5 = b\\2/5 = b\\m = -4/5\\Substitute -new-values-into-slope-intercept-form\\y = mx+b\\y = -4/5x + 2/5[/tex]

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