The graph of F(x), shown below, has the same shape as the graph of
G(X) = x2, but it is shifted up 3 units and to the right 1 unit. What is its
equation?

The graph of Fx shown below has the same shape as the graph of GX x2 but it is shifted up 3 units and to the right 1 unit What is its equation class=

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Answer:

The answer is A.

Step-by-step explanation:

First, recall the vertex form of a quadratic equation: [tex]f(x)=a(x-h)^2+k[/tex], where [tex]h[/tex] represents the horizontal change and [tex]k[/tex] represents the vertical change.

The original equation is [tex]g(x)=x^2[/tex], or, in other words, [tex]g(x)=1(x-0)^2+0[/tex].

We are told that the graph is shifted up 3 and right 1. Thus, both values are positive (right and up). Note that up 3 corresponds to a positive vertical change of 3 while right 1 represents a positive horizontal change of 1.

Thus, put these back into the equation in place of [tex]h[/tex] and [tex]k[/tex].

We have:

[tex]f(x)=1(x-(+1))^2+(+3)[/tex]

Or, simplified:

[tex]f(x)=(x-1)^2+3[/tex]

The answer is A.