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Complete the method, isPerfectSquare(). The method takes in a positive integer, n. It returns a boolean that is true if n is a perfect square, false otherwise. A perfect square is an integer whose square root is also an integer. You may assume that n is a positive integer.
Hint: find the square root of n, cast it to an int value, then square it and compare this square to n.
Starter code:-
public class Square {
public static boolean isPerfectSquare(int n) {
//TODO: complete this method
}
}

Respuesta :

teobguan2019

Answer:

  1. public class Square {
  2.    public static boolean isPerfectSquare(int n){
  3.        int sqrt_n = (int) Math.sqrt(n);
  4.        if(sqrt_n * sqrt_n == n ){
  5.            return true;
  6.        }else{
  7.            return false;
  8.        }
  9.    }
  10. }

Explanation:

Firstly, use sqrt method from Math package to calculate the square root of input n (Line 3). Cast the result to integer and assign it to sqrt_n variable.

Next, square the sqrt_n and check if it is equal to input n (Line 4). If so, return true, if not, return false (Line 4-8).

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