Respuesta :
Answer:
K e q equals StartFraction StartBracket upper C EndBracket superscript lower c StartBracket upper D EndBracket superscript lower D over StartBracket upper A EndBracket superscript lower a StartBracket upper B EndBracket superscript lower b EndFraction.
Explanation:
In order to aid understanding of the question, let me put the words into a proper chemical reaction equation.
aA + bB ⇄cC + dD
We must recall that the equilibrium constant often designated as Keq is given as;
Keq= product of the concentration of product species raised to the power of their respective molar coefficients / product of the concentration of reactant species raised to the power of their respective molar coefficients
Hence from what was written above, I can safely write;
Keq= [C]^c [D]^d / [A]^a [B]^b
This has been represented in words in the answer given above.
The equilibrium constant is simply known too be as equal to the concentration of products over the concentration of reactants.
- The equilibrium constant expression for the given system is K e q equals StartFraction StartBracket upper C EndBracket superscript lower c StartBracket upper D EndBracket superscript lower D over StartBracket upper A EndBracket superscript lower a StartBracket upper B EndBracket superscript lower b EndFraction
Kc Constant is simply known to be a constant for a specific reaction at a particular temperature. The 'c' shows the equilibrium constant as expressed in regards to concentrations.
Kc is also regarded as the equilibrium constant of a chemical reaction.
That is: For the reaction A+B=AB, the equilibrium constant Kc is said to be as [AB]/[A][B].
The equilibrium constant gives us the information we need to know about how far a reaction processes at a specific temperature;
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