60 drops fell from a burret.The first and final readings were 28cm³ and 43cm³ respectively.what is the average volume of one drop

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28-06-2020
Physics

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60 drops fell from a burret.The first and final readings were 28cm³ and 43cm³ respectively.what is the average volume of one drop

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andromache andromache · Answer 1 · 2020-07-03T04:32:52+02:00

Answer:

[tex]0.25\ cm^3[/tex]

Explanation:

Data provided in the question

Number of drops fell from a burret = 60

The first reading is 28 cm^3

And, the final reading is 43 cm^3

Based on the above information, the average volume of one drop is

[tex]= \frac{Final\ readings - first\ readings}{number\ of\ drops}[/tex]

[tex]= \frac{43\ cm^3 - 28\ cm^3}{60 \ drops}[/tex]

[tex]= 0.25\ cm^3[/tex]

Basically we applies the above formula by applying the three items given in the question so that the average volume of one drop could come

Mutio017 Mutio017 · Answer 2 · 2020-09-16T10:23:23+02:00

Answer:

0.25\ cm^30.25 cm

3

Explanation:

Data provided in the question

Number of drops fell from a burret = 60

The first reading is 28 cm^3

And, the final reading is 43 cm^3

Based on the above information, the average volume of one drop is

= \frac{Final\ readings - first\ readings}{number\ of\ drops}=

number of drops

Final readings−first readings

= \frac{43\ cm^3 - 28\ cm^3}{60 \ drops}=

60 drops

43 cm

3

−28 cm

3

= 0.25\ cm^3=0.25 cm

3

60 drops fell from a burret.The first and final readings were 28cm³ and 43cm³ respectively.what is the average volume of one drop​

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60 drops fell from a burret.The first and final readings were 28cm³ and 43cm³ respectively.what is the average volume of one drop