A bar slides vertically between two conducting rails without friction in a magnetic field. The rails are connected via a resistor. The bar reaches a constant velocity and slides for 2m. How much energy is dissipated in the resistor during these 2m's

Respuesta :

Answer:

The energy dissipated is  [tex]E = 9.8 J[/tex]

Explanation:

From the question we are told that

    The distance covered at constant velocity d =  2 m  

      The velocity is  [tex]v = 1.5 \ m/s[/tex]

Generally at constant velocity the magnetic  force on the bar is mathematically represented as

         [tex]F = m * g[/tex]

substituting values

        [tex]F = 0.5 * 9.8[/tex]

        [tex]F = 4.9 \ N[/tex]

The energy dissipated is mathematically evaluate as

         [tex]E = F * d[/tex]

 substituting the value

         [tex]E = 4.9 * 2[/tex]

        [tex]E = 9.8 J[/tex]