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A piece of metal has a mass of 2210 g. The volume of the metal is 260 cm³.

What is the density of the piece of metal?

Respuesta :

mberisso

Answer:

[tex]density= 8.5\,\,\frac{g}{cm^3}[/tex]

Step-by-step explanation:

Recall that the formula for density is:

[tex]density=\frac{mass}{volume}[/tex]

therefore for this case we have:

[tex]density=\frac{mass}{volume} \\density=\frac{2210}{260} \,\frac{g}{cm^3} \\density= 8.5\,\,\frac{g}{cm^3}[/tex]

The density of the piece of metal is 8.5 [tex]\rm g/cm^3[/tex] and this can be determined by using the formula of density.

Given :

  • A piece of metal has a mass of 2210 g.
  • The volume of the metal is 260 cm³.

The density of the piece of metal can be determined by using the formula of density.

The formula of density is given by:

[tex]\rm D = \dfrac{M}{V}[/tex]  --- (1)

where D is the density, M is the mass and V is the volume.

Now, put the value of M that is 2210g and the value of V that is 260 [tex]\rm cm^3[/tex]in the equation (1).

[tex]\rm D = \dfrac{2210}{260}[/tex]

D = 8.5 [tex]\rm g/cm^3[/tex]

So, the density of the piece of metal is 8.5 [tex]\rm g/cm^3[/tex].

For more information, refer to the link given below:

https://brainly.com/question/3074403

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