Respuesta :

Answer:

-21

Step-by-step explanation:

[tex]f(x)=6x^2-22x+12 \\\\\\g(x)=x-3 \\\\\\(f/g)(x)=\dfrac{6x^2-22x+12}{x-3}=\dfrac{(x-3)(6x-4)}{x-3}=6x-4 \\\\\\(f/g)(-3)=6(-3)-3=-18-3=-21[/tex]

Hope this helps!