Respuesta :
For this data set:
Mean: (3+3+4+4+4+5+5+5+5+30) : 10 = 6.8
Mode : 5
Median : (4+5) : 2 =4.5
In this case, the mean is not the best way to show central tendency.
The median is less affected by outliers and skewed data.
Answer: The best measure for the central tendency is the median: 4.5
Mean: (3+3+4+4+4+5+5+5+5+30) : 10 = 6.8
Mode : 5
Median : (4+5) : 2 =4.5
In this case, the mean is not the best way to show central tendency.
The median is less affected by outliers and skewed data.
Answer: The best measure for the central tendency is the median: 4.5
[tex]3, 3, 4, 4, 4, 5, 5, 5, 5, 30[/tex]
[tex]\left[\begin{array}{ccc}Q1&--\\Mean&6.8\\Median&4.5&Correct\\Range&27\end{array}\right][/tex]
First Quartile:
[tex]\left[\begin{array}{ccc}3|3\\4|4\\4|5\\5|5\\5|30\end{array}\right][/tex]
[tex]NotApplicable[/tex]
Mean:
[tex]3, 3, 4, 4, 4, 5, 5, 5, 5, 30[/tex]
[tex]3^{2}+4^{3}+5^{4}+30[/tex]
[tex]\left[\begin{array}{ccc}\frac{68}{10}\end{array}\right][/tex]
[tex]6.8[/tex]
Median:
[tex]\left[\begin{array}{ccc}3, 3, 4, 4, 4, 5, 5, 5, 5, 30\end{array}\right][/tex]
Process Of Elimination
[tex] 4, 5[/tex]
Can't Split up Whole Numbers Any More Than They Are Already So Answer Is
[tex]4.5[/tex]
Range:
[tex]3, 3, 4, 4, 4, 5, 5, 5, 5, 30[/tex]
[tex]30-3[/tex]
[tex]27[/tex]