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A cooler contains ten bottles of sports drink: four lemon-lime flavored, three orange-flavored, and three fruit-punch flavored. Three times, you randomly grab a bottle, return the bottle to the cooler, and then mix up the bottles. The first time, you get a lemon-lime drink. The second and third times, you get fruit-punch.


show work please thanks! 20 poinsssssss!!

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mangococonut12

Since there are a total of 10 bottles, the probability of getting a certain one is based on the number of those bottles in the cooler.

The probability of getting a lemon-lime flavored drink is 4/10 or 40%.

The probability of getting a orange flavored drink is 3/10 or 30%

The probability of getting a fruitpunch flavored drink is also 3/10 or 30%.

If the question is asking what the probability is of choosing lemon-lime, fruit punch and fruit punch again in that order, you would multiply the probabilities together.

.4 * .3 * .3 = .036, so there’s a 3.6% chance of picking these exact 3 flavors happening again.

The probability of when there is four lemon, three orange, three fruit so it should be considered as the 0.036.

Calculation of the probability:

Since

The probability of getting a lemon-lime flavored drink is 40%.

The probability of getting a orange flavored drink is 30%

The probability of getting a fruitpunch flavored drink is also 30%.

So, the probability is

= (40%) (30%) (30%)

= 0.036

Hence, The probability of when there is four lemon, three orange, three fruit should be 0.036.

Learn more about probability here: https://brainly.com/question/16429884?referrer=searchResults

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