Answer:
The velocity of the ball is 3.52 m/s.
Explanation:
A projectile is any object that moves under the influence of gravity and momentum only. Examples are; a thrown ball, a fired bullet, a kicked ball, thrown javelin, etc.
Given that the ball was thrown vertically upward on the top of a skyscraper of height 61.9 m. So that the velocity can be determined by;
u = [tex]\sqrt{\frac{2H}{g} }[/tex]
Where: u is the velocity of the object, H is the height and g is the gravitational force on the object. Given that: H = 61.9 m and g = 10 m/[tex]s^{2}[/tex], then;
u = [tex]\sqrt{\frac{2*61.9}{10} }[/tex]
= [tex]\sqrt{\frac{123.8}{10} }[/tex]
u = 3.5185
The velocity of the ball is 3.52 m/s.
