Answer:
[tex]D=\sqrt{145 }\\[/tex]
Step-by-step explanation:
We are actually using Pythagorean theorem here but to be simple
we can use the equation:
D(distance)=[tex]\sqrt{(x_{1}- x_{2} )^{2} +( y_{1}-y_{2})^{2}}[/tex]
=
[tex]D=\sqrt{(15-3)^{2}+(6-7)^{2} } =\\D=\sqrt{(12)^{2}+(-1)^{2} } =\\\\D=\sqrt{144+1 } =\\D=\sqrt{145 }\\[/tex]
(If you meant 16 instead of 6 the answer would be 15)
Hope this helps!
