Answer:
1/2 or 50%
Explanation:
The probability would be 1/2 or 50%.
Color blindness is generally an X-linked recessive traits. Since males only have one X chromosome, they are either affected or not affected but females with two X chromosomes can be a carrier in addition to being affected or unaffected.
Also, males usually get their X chromosomes from their mothers while the two X chromosomes in females are contributed by each parents.
Let the allele for colour blindness be b.
Genotype of Steve would be [tex]X^bY[/tex]
Since, they produced a male child with color blindness, Mary is a carrier with the genotype: [tex]X^BX^b[/tex]
[tex]X^bY[/tex] x [tex]X^BX^b[/tex]
progeny: X^BX^b (carrier female), X^bX^b (affected female), X^BY (unaffected male), and X^bY (affected male)
Probability of producing color blind children = 2/4 = 1/2
Hence, the probability of their new born baby being color blind remains 1/2 or 50%
