Answer:
0.74176 M HCl
Explanation:
1) Write out a balanced equation.
KOH + HCl --> KCl + H2O
2) Calculate #mol KOH in 76.0mL needed for the titration.
1.22 mol KOH in 1000mL
x mol KOH in 76.0mL
x = 0.09272 mol KOH
3) Use the balanced equation ratio (from step 1), 1 mol KOH : 1 mol HCl.
0.09272 mol KOH = 0.09272 mol HCl
4) 125mL of the HCl solution was used for the titration, so find the molarity.
0.09272 mol HCl is in 125mL
x mol HCl in 1000mL
x = 0.74176 mol HCL / 1 L
SO... 0.74176 M HCl is the answer.
*hope this helped*
- A Kind Stranger
