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Answer:
The mean and standard deviation of the number of trials where the contestant guesses correctly are 12.50 and 3.062.
Step-by-step explanation:
Total number of cards presented to the contestants, N = 4.
Number of cards that has a star printed on it is, x = 1.
The probability of selecting the correct card is:
[tex]P(X)=\frac{x}{N}=\frac{1}{4}=0.25[/tex]
It is provided that each contestant attempts to identify which card has the star on it for a series of n = 50 trials.
Each trial's outcome is independent of other outcomes.
The success of each trial is denoted by the correct selection of the card with a star.
The random variable X can be explained by the Binomial distribution.
So, X follows a Binomial distribution with parameters n = 50 and p = 0.25.
The mean and standard deviation of a Binomial distribution are:
[tex]\text{Mean}=np\\\\\text{SD}=\sqrt{np(1-p)}[/tex]
Compute the mean and standard deviation of the number of trials where the contestant guesses correctly as follows:
[tex]\text{Mean}=np=50\times 0.25=12.50\\\\\text{SD}=\sqrt{np(1-p)}=\sqrt{50\times 0.25\times (1-0.25)}=3.062[/tex]
Thus, the mean and standard deviation of the number of trials where the contestant guesses correctly are 12.50 and 3.062.
[tex]N = 4[/tex] is the overall number of points distributed to the contestant, [tex]x = 1[/tex] reflects the number of decks with a star on them. The probability of selecting the correct card is as follows:
[tex]\to P(X)=\frac{x}{N}=\frac{1}{4}=0.25[/tex]
- For a total of n = 50 trials, each competitor must determine whichever card has the star on it.
- The result of each trial is different from the results of the others.
- A proper selection of a card with such a star shows the success of each trial.
- The Binomial distributions can account for such a random value of x, As a result, X has a binomial distribution having values [tex]n = 50[/tex] and [tex]p = 0.25[/tex].
- The Binomial distribution does have the following mean and standard deviation:
[tex]\to \text{Mean =np}\\\\\to \text{SD}=\sqrt{np(1-p)}\\\\[/tex]
- Determine the mean difference of the number of tests where the contender correctly guesses:
[tex]\to \text{Mean =np}= 50 \times 0.25= 12.5\\\\[/tex]
[tex]\to SD=\sqrt{np(1-p)}[/tex]
[tex]=\sqrt{50 \times 0.25 \times (1-0.25)}\\\\=\sqrt{50 \times 0.25 \times (0.75)}\\\\= \sqrt{12.5 \times 0.75}\\\\=\sqrt{9.375}\\\\=3.061[/tex]
As just a result, the standard deviation of the number most right guesses by the competitor are [tex]12.50 \ \ and\ \ 3.061[/tex], correspondingly.
Learn more about the contestant guesses:
brainly.com/question/1302166
