Answer:
The relaxed length of spring was 61 cm
Explanation:
To solve this problem, we will use Hooke's Law. Hooke's law is stated as:
F = k Δx
F = k(x - x₀)
where,
F = Force applied to the spring = 133 N
k = Spring Constant = 730 N/m
x = Total Length after elongation = 79 cm = 0.79 m
x₀ = Initial or Relaxed Length of Spring = ?
Therefore,
133 N = (730 N/m)(0.79 m - x₀)
(0.79 m - x₀) = (133 N)/(730 N/m)
(0.79 m - x₀) = 0.18 m
x₀ = 0.79 m - 0.18 m
x₀ = 0.61 m = 61 cm
