Respuesta :

Let us subtract equation 1 from equation 2.

5x - 3y - 2x + 3y = 7 - 4

3x = 3

x = 1

Substituting this value of x in equation 1, we get

2x - 3y = 4

2 - 3y = 4

-3y = 2

y = [tex]\frac{-2}{3}[/tex]

For a system of equations to have no real solution, the lines of the equations must be parallel to each other. The solution of the system of equation will be at (1, -2/3).

What is a System of equations?

Inconsistent System

For a system of equations to have no real solution, the lines of the equations must be parallel to each other.

Consistent System

1. Dependent Consistent System

For a system of the equation to be a Dependent Consistent System, the system must have multiple solutions for which the lines of the equation must be coinciding.

2. Independent Consistent System

For a system of the equation to be an Independent Consistent System, the system must have one unique solution for which the lines of the equation must intersect at a particular.

Use can solve the given system of equations using the combination method as shown below.

1. Subtract the first equation from the second equation.

5x - Зу - (2x - 3y) = 7 - 4

5x - 3y -2x + 3y = 3

3x = 3

x = 1

2. Substitute the value of x in any one of the equation.

5x - 3y = 7

5(1) - 3y = 7

5 - 3y = 7

-3y = 7 - 5

y = -(2/3)

Hence, the solution of the system of equation will be at (1, -2/3).

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