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How many grams of solute are needed to make 2.66L of a 1.99M C 12 H 22 O 11 solution?

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DrMantisToboggan

Answer:

1812g

Explanation:

So molarity is moles/litres or M= mol/liter (lets apply this formula to find moles)

M=mol/L

1.99=mol/2.66

Moles= 5.2934 moles of C12H22O11

Next step is quite simple, we know molar mass of C12H22O11 is 342.3 g/mol so we simply multiply the moles we get to molar mass we are left with the grams needed,

5.2934 moles of C12H22O11 * 342.3 g C12H22O11 /mol = 1812g

(I have left out decimal places, you can caculate this and add them if you desire)

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