Answer:
16
Step-by-step explanation:
The area of one envelope can be considered to be the sum of the areas of ...
- a 14cm x 30 cm triangle: A = (1/2)(14 cm)(30 cm) = 210 cm^2
- a 32 x 20 rectangle: A = (32 cm)(20 cm) = 640 cm^2
- a 30 x 20 rectangle: A = (30 cm)(20 cm) = 600 cm^2
for a total of ...
(210 +640 +600) cm^2 = 1450 cm^2
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The area of one sheet of paper is ...
A = LW = (130 cm)(220 cm) = 28600 cm^2
The ratio of paper area to envelope area is ...
28600/1450 ≈ 19.7
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Considered as a 32 cm by 54 cm rectangle, the area of the envelope is ...
A = (32 cm)(54 cm) = 1728 cm^2
and the ratio of paper area to envelope area is ...
28600/1728 ≈ 16.6
That is, considering space utilization, the best that can be done is to cut 16 envelopes from each sheet of paper.
