Answer:
[tex]n=0.0564mol[/tex]
Explanation:
Hello,
In this case, since iodine is ideal we can use the ideal gas equation to compute the moles at the given conditions, considering the following units:
[tex]V=1250mL*\frac{1L}{1000mL} =1.25L\\P=768mmHg*\frac{1atm}{760mmHg}=1.01atm\\ T=10+273.15=283.15K[/tex]
[tex]PV=nRT[/tex]
[tex]n=\frac{PV}{RT} =\frac{1.01atm*1.25L}{0.082\frac{atm*L}{mol*K}*273.15K} \\\\n=0.0564mol[/tex]
Best regards.
