Answer:
Step-by-step explanation:
The figure is missing. However, we can solve the second problem.
We know there are 7 balls in total, 2 black and 5 white.
Amy draws two balls. Assuming that the balls aren't replaced after being picked, we have
[tex]P=\frac{5}{7} \times \frac{4}{6} = \frac{20}{42}=\frac{10}{21} \approx 0.48[/tex]
Therefore, the probability of getting two white balls is 10/21, which is equivalent to 48% approximately.